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电动机启动方式对比

比较 DOL、星三角、软启动和变频启动。

无标准

输入

使用默认输入值的示例计算。

轴功率
11 kW
线电压
400 V
功率因数
0.85
效率
0.9
堵转电流
6 x
堵转转矩
200 %
负载脱离转矩
30 %
自耦变压器抽头
65 %
一次侧电阻,电机端电压
70 %
软启动器限流值
3.5 x
驱动器电流限值
150 %
电动机处的短路电流水平
0 kA

启动负载的最低启动电流

变速驱动器

满载电流
20.75A
启动电流,DOL
124.5A
所选方法的启动电流
31.13A
所选方法的启动转矩
150%

此结果仅供设计参考。请对照现行标准进行核验。

计算步骤

  1. 满载电流20.75A

    Induction motor at standstill: current with the voltage, torque with its square.

  2. 满载转矩72.2Nm
  3. 堵转电流124.5A
  4. 堵转转矩200%
  5. 负载脱开转矩30%
  6. 启动电流,Direct on line124.5A
  7. 启动转矩,Direct on line200%
  8. 启动电流,Star-delta41.5A
  9. 启动转矩,Star-delta66.7%
  10. 启动电流,Autotransformer52.6A
  11. 启动转矩,Autotransformer84.5%
  12. 启动电流,Primary resistance87.15A
  13. 启动转矩,Primary resistance98%
  14. 启动电流,Soft starter72.63A
  15. 启动转矩,Soft starter68.1%
  16. 启动电流,Variable speed drive31.13A
  17. 启动转矩,Variable speed drive150%

关于此计算器

How this is calculated

You give the motor's shaft power, line voltage, power factor and efficiency. The tool works the full load current and full load torque the same way the motor tool does. Then you give the locked-rotor current and torque from the motor data, and the torque the load needs to break away from rest.

A cage induction motor at standstill behaves like a transformer with its secondary shorted. Its current follows the voltage at its terminals, and its torque follows the square of that voltage. Every starting method is a way of lowering the voltage at the motor, or of controlling the current directly. So the tool scales the locked-rotor current and torque for each method:

  • direct on line takes the full locked-rotor current and torque;
  • star-delta puts the line voltage divided by the square root of 3 across each winding, so the line current and the torque both fall to a third;
  • an autotransformer at a tap gives the motor the tap voltage; the motor current falls with the tap, the line current and the torque with the tap squared;
  • primary resistance leaves part of the voltage at the motor; the current falls with it, the torque with its square;
  • a soft starter holds the current at its limit, and the torque falls with the square of that limit over the locked-rotor current;
  • a drive starts at rated flux, so its torque follows its current limit.

A method starts the load where its starting torque is above the breakaway torque. With a fault level at the motor terminals, the tool estimates the dip as the starting current over the fault current.

StepTable or clauseWhat it decides
Full load current and torqueThe motor tool's methodThe base for every multiple
Direct on lineLocked-rotor dataThe highest current and torque
Star-deltaOne third of eachThe current and torque in star
Autotransformer and primary resistanceVoltage ratio and its squareThe current and torque at the tap
Soft starter and driveCurrent limitThe current and torque each allows
Starts the loadBreakaway torqueWhich methods start it

Worked examples

  • An 11 kW centrifugal pump. Every method starts it. Direct on line draws 124.5 A and star-delta 41.5 A. The lowest start that still turns the pump is the variable speed drive, at 31.13 A.
  • A 22 kW loaded conveyor. Star-delta gives 73.3 % torque against a 120 % load, so it cannot start the belt. The lowest start that does is direct on line, at 290.57 A.
  • A 37 kW fan on a board with 6 kA. The dip is 8.1 % direct on line and 2.7 % in star-delta. The lowest start is the variable speed drive, at 104.72 A and a 1.7 % dip.
  • A 5.5 kW bore pump at the end of a rural line. Direct on line dips the supply 9.1 %, a soft starter at 3.5 times full load current 4.5 %. The lowest start is the variable speed drive, at 15.57 A.

Limits

The comparison is at standstill. It does not follow the torque through the run-up, so a star-delta start that breaks the load away can still stall before the change to delta. The drive figures assume rated flux; the supply side of a drive draws less than the motor side at low speed. The dip is an estimate for comparing methods, not a flicker study. Choose the circuit-breaker so its magnetic trip clears the starting current of the method used, and set the overload to the full load current.

See also: Motor starting methods: current and torque, Starting a loaded conveyor and Motor.

问题

结果仅供设计参考。请依据现行标准核对。

星三角启动可将启动电流降低多少?

降至直接启动(DOL)电流的三分之一,因为启动时每个绕组承受的是线电压除以根号 3 的电压。启动转矩同样降至三分之一。

星-三角启动能启动我的负荷吗?

仅当堵转转矩的三分之一高于负荷脱开转矩时适用。风机或离心泵通常可以启动;满载输送机或破碎机往往无法启动。工具会标记每种能启动负荷的方式。

自耦变压器抽头有什么作用?

在 65 % 抽头时,电动机承受的电压为 65 %。电动机电流和转矩随抽头降低,线路电流随抽头的平方下降,因此 65 % 抽头所取电流约为直接启动(DOL)电流的 42 %。

为何变频器在启动时电流最小?

变频器以额定磁通在低频下启动电动机,因此在接近满载电流时即可提供满载转矩。本工具将变频器的电流限值作为启动电流和转矩。

电压跌落如何计算?

以启动电流与电动机端子处预期短路电流之比表示。这是一种估算,假定电源与启动采用相同的功率因数。请用于比较各种方法,而非作为闪变研究。

计算示例

背景

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