谐波、中性线电流及 k 系数
根据频谱求出 THD、中性线电流及 k 系数。
Reads AS/NZS 3000:2018, AS/NZS 3008.1.2:2017 (NZ) and AS/NZS 3008.1.1:2017 (AU). Tables checked 2 Oct 2026.
尝试一个工程 4
每项工作都会预填示例数值。请替换为您自己的数值。
- Find the harmonic neutral current of an officeThe neutral current of an office floor full of computers, from its spectrum.
- Find the K-factor for a drive transformerThe K-factor of six-pulse drives, for the transformer that feeds them.
- Check an LED lighting circuit for harmonicsWhether a cable for LED drivers is picked on its neutral current.
- Neutral current with some electronic loadThe neutral of a board where electronics are 30 % of the load.
输入
使用默认输入值的示例计算。
- 管辖区
- NZ · AS/NZS 3008.1.2
- 相电流,真有效值
- 100 A
- Third harmonic
- 35 %
- Fifth harmonic
- 20 %
- Seventh harmonic
- 10 %
- Ninth harmonic
- 5 %
- Eleventh harmonic
- 4 %
- Thirteenth harmonic
- 3 %
- Fifteenth harmonic
- 2 %
- 产生谐波的相负载比例
- 100 %
- 不平衡电流
- 0 A
三次谐波中性线
97.88A
- 电流总谐波畸变率
- 42.18%
- K 系数
- 3.59
- Table 2 折减系数
- ×0.86
- 所选电缆
- 相电流
- 选择电缆所依据的电流
- 116.28A
- Cl 3.5.2(b)(i) 中性线最小值
- 38.86A
此结果仅供设计参考。请对照现行标准进行核验。
计算步骤
- 电流总谐波畸变率42.18%
- 基波电流92.14A
- 三次谐波倍数,√(h3² + h9² + h15²)35.41%
- 三次谐波中性线结果97.88A
- 三次谐波,占相电流的百分比32.25%
AS/NZS 3008.1.2:2017 Table 2
- Table 2 折减系数×0.86
AS/NZS 3008.1.2:2017 Table 2
- 仅三次谐波中性线电流96.75A
AS/NZS 3008.1.2:2017 Cl 3.5.9
- 选择电缆所依据的电流116.28A
AS/NZS 3008.1.2:2017 Cl 3.5.9
- 单相的谐波电流,三次及以上38.86A
- Cl 3.5.2(b)(i) 中性线最小值38.86A
AS/NZS 3000:2018 Cl 3.5.2(b)(i)
- K 系数3.59
关于此计算器
How this is calculated
Electronic loads draw current in pulses, not as a smooth wave. A power quality analyser splits that current into the fundamental and its harmonics, each shown as a percent of the fundamental. The tool takes the true rms phase current and that spectrum, from the third to the fifteenth order.
The total harmonic distortion is the rms of all the harmonic percents. The fundamental current is the rms current divided by the square root of one plus the distortion squared.
The third, ninth and fifteenth harmonics are the triplens. In the three phases they are in step, so they add in the neutral instead of cancelling. With equal phases the neutral carries three times one phase's triplen current. That is the tool's main answer.
AS/NZS 3008.1 Table 2 bands the third harmonic as a percent of the phase current. So the tool converts the analyser's percent of the fundamental to a percent of the rms current. It reads the band through the cable size tool's own path, and gives the reduction factor, whether the cable is picked on the phase or the neutral current, and the current to carry to cable size.
AS/NZS 3000 Cl 3.5.2(b)(i) gives a minimum for the neutral of a substantial harmonic load: the out-of-balance current plus one phase's harmonic current. Size the neutral for the larger of it and the triplen figure. AmpSize reads the harmonic current as the rms of the third and higher orders. Note 1 sets what substantial means.
The K-factor weights each harmonic by its order squared, because eddy current loss in a transformer rises with frequency squared. A clean load gives 1.
| Step | Table or clause | What it decides |
|---|---|---|
| Distortion | The rms of the harmonic percents | The THD and the fundamental current |
| Triplen neutral | Three times one phase's triplens | The neutral current of three equal phases |
| Third harmonic band | Table 2 | The reduction factor and the basis the cable is picked on |
| Neutral of the third harmonic | Cl 3.5.9 | The current the cable is picked on above the middle band |
| Clause neutral | Cl 3.5.2(b)(i) | The out-of-balance current plus one phase's harmonic current |
| Substantial load | Cl 3.5.2(b)(i) Note 1 | Whether the clause figure applies |
| K-factor | Each order squared, weighted by its share | The transformer K rating to pick at or above |
Worked examples
- An office floor of 80 A with 40 % third harmonic puts 87.16 A in the neutral, more than a phase. The current has 49.34 % THD and a K-factor of 4.37.
- Six-pulse drives drawing 150 A put only 13.43 A in the neutral, as their harmonics are mostly fifth and seventh. The current has 35.14 % THD and a K-factor of 5.12.
- An LED lighting circuit of 40 A puts 64.28 A in the neutral. The current has 89.16 % THD and a K-factor of 10.01.
- A 60 A board where electronics are 30 % of the load puts 58.73 A of triplens in the neutral if every load had this spectrum. The current has 42.18 % THD and a K-factor of 3.59. Below 40 % the clause figure does not apply.
Limits
The tool assumes three equal phases with the same spectrum. A real board has a mix. Enter the worst phase's readings for a safe answer.
It does not work voltage distortion, resonance with power factor capacitors or filter design. Those need the supply's impedance and a harmonic study.
See also: Neutral current, Cable size and Transformer.
问题
结果仅供设计参考。请依据现行标准核对。
如何计算谐波中性线电流?
三相中的三次、九次和十五次谐波同相位,因此在中性线中叠加。各相平衡时,中性线电流为单相三倍次谐波电流。工具根据相电流和频谱计算。
电流的 THD 是什么?
总谐波畸变率为所有谐波电流有效值与基波电流之比,以百分比表示。分析仪以各次谐波占基波的百分比显示。本工具采用这些数值,并给出 THD 和基波电流。
什么是 K 系数?
工具按谐波次数的平方对每个谐波加权,因为变压器中的涡流损耗随频率平方增加。无谐波的负荷为 K-1。选择不低于该数值的变压器 K 额定值。额定值档位不在 AmpSize 所收录的标准中。
何时按中性线电流确定电缆截面?
AS/NZS 3008.1 Table 2 将三次谐波按相电流的百分比划分区间。超过 33 % 时,电缆按中性线电流选取。本工具给出系数、依据以及用于电缆截面选型的电流。
AS/NZS 3000 对谐波负荷有什么要求?
Cl 3.5.2(b)(i) 将三次及以上谐波电流计入中性线的不平衡电流,取最高一相谐波电流的 100 %。Note 1 规定,谐波负荷达到某相负荷的 40 % 或以上时属于较大。
本工具读取的条款和表格
- AS/NZS 3000:2018 Cl 3.5.2(b)Neutral of a multiphase circuit
- AS/NZS 3008.1.2:2017 Cl 3.5.9Third harmonic current in the neutral
- AS/NZS 3000:2018 Cl 3.5.2Neutral conductor of a circuit
- AS/NZS 3008.1.2:2017 Table 2Reduction factors for harmonic currents in 4- and 5‑core cables
- AS/NZS 3008.1.1:2017 Table 2Reduction factors for harmonic currents in 4- and 5‑core cables
表格最后核对于 2 Oct 2026。
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